Someday I was given such a question, two-player(A, B) and 4 slots, each player put "N" or "O" to these slots, who first spell 'NON' win this game. Is there a strategy player A or player B will be a sure success? I am not very familiar with this, so he gives some hints for the below case, B will succeed no matter what A puts.
[N(A puts) |_ | _ | N(B puts)]
First A put N at the first index of this array, then B put N at the last position. Then no matter what and where A puts, B will win.
So the question is if the slots are added to 7 slots, is there the same strategy?
[ _ |_ | _ | _ | _ | _ | _ ]
I thought a way similar to cases of four slots, however, it needs such preconditions. I am not sure whether there's some theory behind that.
[ N |_ | _ | N | _ | _ | N ]