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in Java by (9.5k points)

Below is the code I’ve to catch and show the exception message: 

try

{

    String name = null;

    System.out.println("name=" + name.toString());

}

catch(Exception e)

{

    System.out.println("Exception Occured" + e.getMessage());

}

Can anyone tell me a proper way to avoid NullPointerExceptions? 

1 Answer

0 votes
by (19.7k points)

To reduce NullPointerExceptions, never return null from your methods like below: 

public IList<String> getUserNames()

{

     //No usernames found...

     return new ArrayList<String>();

     //As opposed to returning null

     return null;

}

This will return the empty list and result into for(String name :

this.getUserNames()) {...}. 

But if you want to return null, you have to do something like below: 

List<String> userNames = this.getUsernames();

if(userNames != null)

     for(String userName : userNames) {....}

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