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Is there an equivalent to the MATLAB
size()
command in Numpy?
In MATLAB,
>>> a = zeros(2,5) 0 0 0 0 0 0 0 0 0 0 >>> size(a) 2 5
>>> a = zeros(2,5)
0 0 0 0 0 0 0 0 0 0
>>> size(a)
2 5
In Python,
>>> a = zeros((2,5)) >>> array([[ 0., 0., 0., 0., 0.], [ 0., 0., 0., 0., 0.]]) >>> ?????
>>> a = zeros((2,5))
>>> array([[ 0., 0., 0., 0., 0.],
[ 0., 0., 0., 0., 0.]])
>>> ?????
To calculate the size of NumPy array you can use the "shape" in NumPy, and can be requested via the .shape attribute:
>>> a = zeros((2, 5)) >>> a.shape (2, 5)
>>> a = zeros((2, 5))
>>> a.shape
(2, 5)
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