Retrieving the output of subprocess.call()

Question

How can I get the output of a process run using subprocess.call()?

Passing a StringIO.StringIO object to stdout gives this error:

Traceback (most recent call last): 

File "<stdin>", line 1, in <module>   File"/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/subprocess.py", line 444, in call return Popen(*popenargs, **kwargs).wait() 

File"/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/subprocess.py", line 588, in __init__ errread, errwrite) = self._get_handles(stdin, stdout, stderr) 

File"/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/subprocess.py", line 945, in _get_handles 

c2pwrite = stdout.fileno() 

AttributeError: StringIO instance has no attribute 'fileno' 

>>>

Answer 1

You can use the below-mentioned code for retrieving the output of subprocess.call():-

from subprocess import Popen, PIPE
p = Popen(['program', 'arg1'], stdin=PIPE, stdout=PIPE, stderr=PIPE) 

output, err = p.communicate(b"input data that is passed to subprocess' stdin") 

rc = p.returncode