0 votes
1 view
in Python by (1.6k points)

 I have a dictionary: keys are strings, values are integers.

Example:

stats = {'p':4000, 'q':8000, 'r': 900}

I'd like to get 'q' as an answer, since it's the key with a higher value.

I did the following, using an intermediate list with reversed key-value tuples:

inverse = [(value, key) for key, value in stats.items()]

print max(inverse)[1]

Is that one the better (or even more elegant) approach? 

2 Answers

0 votes
by (10.9k points)
edited by

You can use the operator.itemgetter(items) ,it returns a callable object which fetches item from its operand using _getitem_() method of the operand.

To use operator.itemgetter() use this code:

import operator

stats = {'p':4000, 'q':8000, 'r': 900}

max(stats.iteritems(), key=operator.itemgetter(1))[0]

In the above max() function, you have the “key” parameter is a function which compares elements to find the maximum between them. You may also use stats.iteritems() since it minimizes the memory use by eliminating the need for creating a new list.

Note:

In case you have:

stats = {'p':4000, 'q':8000, 'r': 900,‘s’:8000}

Then don’t expect the function to return both the maximum values ‘q’ and ‘s’,it will only return either of the two i.e, either ‘q’ or ‘s’ and not both.

Ex-

>>> import operator

>>> stats = {'p':4000, 'q':8000, 'r': 900,‘s’:8000}

>>> max(stats.iteritems(), key=operator.itemgetter(1))[0]

's’

For Python 3, replace stats.iteritems() with stats.items().

Hope this helps!

 

0 votes
by (20.3k points)

You can try using the code given below:

max(stats, key=stats.get)

OR

You can just try doing this:

stats = {'a':1000, 'b':3000, 'c': 100}

max(stats.iterkeys(), key=lambda k: stats[k])

Here, the function key simply returns the value that should be used for ranking and max() returns the demanded element right away.

Related questions

Welcome to Intellipaat Community. Get your technical queries answered by top developers !


Categories

...