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I have the script, but I do not know how to get this last element in one printout:

cat /proc/cpuinfo | awk '/^processor/{print $3}'

The last element should hold the number of CPUs, minus 1.

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Use the below command:

grep -c ^processor /proc/cpuinfo     

will count the number of lines starting with

"processor" in /proc/cpuinfo

For systems with hyper-threading, you can use

grep ^cpu\\scores /proc/cpuinfo | uniq |  awk '{print $4}' 

which should return  8 

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