Python: How to sort an array with integers and letters?

Question

At the point when I have a list of integers and letters, I need to sort these components by some request. For instance, 

ex_array = [1, 3, 2', 2, 1', 3', 3]

This should be sorted as:

sorted(ex_array) = [1', 1, 2', 2, 3', 3, 3]

In case, the order of the letters is given by,

1' < 1 < 2' < 2 < 3' < 3.

I can also make a code when comprising of just integers. Be that as it may, I don't have a clue how to contrast the symbols with primed with unprimed. 

Would you be able to guide me in Python?

Answer 1

Sort by the integer value of every component, just as whether that component is an integer:

>>> a = [1, 3, '2', 2, '1', '3', 3, '10', 10, 'potato', "1'", lambda: None, '-3', -3, -4]

>>> sorted(a, key=lambda x: (int(''.join(v for i,v in enumerate(str(x)) if v.isdigit() or (i==0 and v=='-')) or 0), isinstance(x, int)))

[-4, '-3', -3, 'potato', '1', "1'", 1, '2', 2, '3', 3, 3, '10', 10, <function <lambda> at 0x000000DAD51DB9D8>]

On the off chance that two components have a similar integer value, the string will be set before the integer.

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