How to determine whether a year is a leap year?

Question

I'm attempting to make a basic program to decide if a specific year is a leap year. 

By definition, a leap year is actually divisible by four, yet not by 100, except if it is divisible by 400. 

Here is my code:

def leapyr(n):

    if n%4==0 and n%100!=0:

        if n%400==0:

            print(n, "is a leap year.")

    elif n%4!=0:

        print(n, "is not a leap year.")

print(leapyr(1900))

 

At the point when I attempt this inside the Python IDLE, the module returns None back. I'm almost certain that I ought to get

1900 is a leap year

Answer 1

You can try using calendar.isleap :

import calendar

print(calendar.isleap(1900))

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