Write a python function for leap year

Question

Kindly assistance me with this code as it continues to give "None" as yield at whatever point a non leap year is input 

def is_leap(year):

if year >=1900:

    if year%4==0:

        if year%100==0:

            if year%400==0:

                print ("True")

            else:

                print ("False")

        else:

            print("True")

    else:

        print("False")

year = int(input())

print(is_leap(year))

Answer 1

You didn't indicate the input and the function appears to be not finished to me however in the given example when your input parameter year is under 1900 (In the second line of the function) at that point the function will not print anything.

def is_leap(year):

    if year >=1900:

        if year%4==0:

            if year%100==0:

                if year%400==0:

                    return True

                else:

                    return False

            else:

                return True

        else:

            return False

    return False

year = input()

print(is_leap(year))

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