In your code, the issue arises because you convert the items in the list to integers without updating the list itself with the converted values. Furthermore, the default behavior of the sort() function is to perform a lexicographic sort, treating the items as strings rather than numbers.
To achieve the desired sorting based on numerical values, you can utilize the key parameter of the sort() function. Here's an updated version of your code:
list1 = ["1", "10", "3", "22", "23", "4", "2", "200"]
list1 = [int(item) for item in list1] # Convert items to integers
list1.sort(key=int) # Sort the list based on integer values
print(list1)
Output:
[1, 2, 3, 4, 10, 22, 23, 200]
In this updated code, a list comprehension is used to iterate over list1 and convert each item to an integer. The list is then sorted using the sort() function with the key parameter set to int. By specifying key=int, Python understands that the sorting should be based on the integer values of the items in the list.
By implementing these changes, you will obtain the desired output, with the list sorted in ascending order according to the numerical values.