Python dateutil.parser.parse parses month first, not day

Question

I'm utilizing dateutil.parser.parse to arrange a date from a string. Be that as it may, presently it stirs up the month and the day. 

I have a string that contains 05.01.2015. After

dateutil.parser.parse("05.01.2015")

it returns:

datetime.datetime(2015, 5, 1, 0, 0)

I thought it would return (2015,5,1,0,0)

How might I tell the code that the arrangement is dd.mm.yyyy? 

For the record, 25.01.2015 will be parsed as (2015, 1, 25, 0, 0), true to form.

Answer 1

To address the issue of the day and month being interchanged when using dateutil.parser.parse() in Python, you can explicitly indicate the date format as "dd.mm.yyyy" by setting the dayfirst parameter to True. Here's a rephrased explanation:

from dateutil.parser import parse

date_string = "05.01.2015"

parsed_date = parse(date_string, dayfirst=True)

print(parsed_date)

By specifying dayfirst=True, the code correctly recognizes the date format as "dd.mm.yyyy" and parses the date accordingly. Consequently, the parsed result will be (2015, 1, 5, 0, 0) instead of (2015, 5, 1, 0, 0).

By explicitly indicating dayfirst=True, you inform the parser to interpret the first value as the day, the second value as the month, and the third value as the year. This ensures accurate parsing based on the desired date format.

Answer 2

You can just specify dayfirst=True:

>>> dateutil.parser.parse("05.01.2015", dayfirst=True)

datetime.datetime(2015, 1, 5, 0, 0)

This offers priority to the DD-MM-YYYY format rather than MM-DD-YYYY in situations where the date design is uncertain (for example at the point when the day is 12 or lower)

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Answer 3

To specify the date format as "dd.mm.yyyy" when using dateutil.parser.parse() in Python, you can pass the dayfirst=True argument to indicate that the day comes before the month in the string. Here's an example:

from dateutil.parser import parse

date_string = "05.01.2015"

parsed_date = parse(date_string, dayfirst=True)

print(parsed_date)

The output will be:

2015-01-05 00:00:00

By setting dayfirst=True, you are instructing the parser to interpret the first value as the day, the second value as the month, and the third value as the year. This ensures that the date is correctly parsed as "05.01.2015" with the day preceding the month.

Answer 4

When using dateutil.parser.parse() in Python, if the day and month are being mixed up in the parsed result, you can specify the date format explicitly using the dayfirst=True parameter. Here's how you can modify your code:

from dateutil.parser import parse

date_string = "05.01.2015"

parsed_date = parse(date_string, dayfirst=True)

print(parsed_date)

With dayfirst=True, the code correctly interprets the date format as "dd.mm.yyyy". As a result, the parsed date will be (2015, 1, 5, 0, 0) instead of (2015, 5, 1, 0, 0).

By explicitly specifying dayfirst=True, you inform the parser to consider the first value as the day, the second value as the month, and the third value as the year. This ensures that the date is parsed correctly based on the desired date format.

Answer 5

To resolve the issue of the month and day being mixed up when using dateutil.parser.parse() in Python, you can provide the date format explicitly by setting dayfirst=True. Here's an alternative phrasing:

from dateutil.parser import parse

date_string = "05.01.2015"

parsed_date = parse(date_string, dayfirst=True)

print(parsed_date)

By including dayfirst=True, the code interprets the date format as "dd.mm.yyyy" and parses the date accordingly. In this case, the parsed result will be (2015, 1, 5, 0, 0) rather than (2015, 5, 1, 0, 0).

By explicitly specifying dayfirst=True, you instruct the parser to consider the first value as the day, the second value as the month, and the third value as the year. This ensures that the date is correctly parsed based on the intended date format.