Can someone please explain why this statement gives the output as 'A', print (('A','B')[a == False]) . Initial value of a = True [duplicate]

Question

I need an explanation of why the output is A for the following code is.

a = True

print (('A','B')[a == False])

Answer 1

Assuming the first line is a = True, a == False evaluates to false, therefore the boolean value of 0. Therefore your expression is same as the print(('A', 'B')[0]) which prints 'A'

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