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+5 votes
2 views
in Data Science by (17.6k points)

I'm trying to predict heart disease of patients using liner regression algorithm in machine learning and I have this error(only integers, slices (:), ellipsis (...), numpy.newaxis (None) and integer or boolean arrays are valid indices) can anyone please help me to solve it?

  import pandas

    import numpy as np

    from sklearn.linear_model import LinearRegression

    from sklearn.cross_validation import KFold

    heart = pandas.read_csv("pc.csv")

    heart.loc[heart["heartpred"]==2,"heartpred"]=1

    heart.loc[heart["heartpred"]==3,"heartpred"]=1

    heart.loc[heart["heartpred"]==4,"heartpred"]=1

    heart["slope"] = heart["slope"].fillna(heart["slope"].median())

    heart["thal"] = heart["thal"].fillna(heart["thal"].median())

    heart["ca"] = heart["ca"].fillna(heart["ca"].median())

    print(heart.describe())

    predictors=["age","sex","cp","trestbps","chol","fbs","restecg","thalach","exang","oldpeak","slope","ca","thal"]

    alg=LinearRegression()

    kf=KFold(heart.shape[0],n_folds=3, random_state=1)

    predictions = []

    for train, test in kf:

        # The predictors we're using the train the algorithm.  

        train_predictors = (heart[predictors].iloc[train,:])

        print(train_predictors)

        # The target we're using to train the algorithm.

        train_target = heart["heartpred"].iloc[train]

        print(train_target)

        # Training the algorithm using the predictors and target.

        alg.fit(train_predictors, train_target)

        # We can now make predictions on the test fold

        test_predictions = alg.predict(heart[predictors].iloc[test,:])

        predictions.append(test_predictions)

    # The predictions are in three separate numpy arrays.  Concatenate them into one.  

    # We concatenate them on axis 0, as they only have one axis.

    predictions = np.concatenate(predictions, axis=0)

    # Map predictions to outcomes (only possible outcomes are 1 and 0)

    predictions[predictions > .5] = 1

    predictions[predictions <=.5] = 0

    i=0.0

    count=0

    for each in heart["heartpred"]:

        if each==predictions[i]:

            count+=1

        i+=1

    accuracy=count/i

    print("Linear Regression Result:-")

    print("Accuracy = ")

    print(accuracy*100)

Error shown below:

File "C:\Users\Khadeej\Anaconda3\lib\site-packages\spyder\utils\site\sitecustomize.py", 

line 705, in runfile execfile(filename, namespace) File "C:\Users\Khadeej\Anaconda3\lib\site-packages\spyder\utils\site\sitecustomize.py", 

line 102, in execfile exec(compile(f.read(), filename, 'exec'), namespace) File "C:/Users/Khadeej/Desktop/Heart-Disease-Prediction-master/linear.py", 

line 39, in <module> if each==predictions[i]: 

IndexError: only integers, slices (:), ellipsis (...), numpy.newaxis (None) and integer or boolean arrays are valid indices

7 Answers

+6 votes
by (41.4k points)

Here i=0.0 means that i is a float. So, we cannot index a numpy array with a float number.

    # Map predictions to outcomes (only possible outcomes are 1 and 0)

    predictions[predictions > .5] = 1

    predictions[predictions <=.5] = 0

    # Change to an integer

    i = 0

    count = 0

    for hpred in heart["heartpred"]:

        if hpred == predictions[i]:

            count += 1

        i+=1

    accuracy=count/i

    print("Linear Regression Result:-")

    print("Accuracy = ")

    print(accuracy*100)

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"How to fix: 'only integers, slices (`:`), ellipsis (`…`), numpy.newaxis (`None`) and integer or boolean arrays are valid indices'?
Intellipaat-community
by (107k points)
Yup, it worked for me!!! Thank You so much :)
by (19.7k points)
Very well explained!
by (33.1k points)
It also solved my problem.
Thanks.
by (19.9k points)
This worked for me. Thanks.
+3 votes
by (29.5k points)
I think shlok's answer is correct as you are trying to index a numpy array with float that is not correct change that and i think you are good to go
"How to fix: 'only integers, slices (`:`), ellipsis (`…`), numpy.newaxis (`None`) and integer or boolean arrays are valid indices'?
Intellipaat-community
by (44.4k points)
Yes, that's true
+1 vote
by (47.2k points)

I think that problem is your while loop, n is divided by 2, but never cast as an integer again, so it becomes a float at some point. It is then added onto y, which is then a float too, and that gives you the warning.

"How to fix: 'only integers, slices (`:`), ellipsis (`…`), numpy.newaxis (`None`) and integer or boolean arrays are valid indices'?
Intellipaat-community
by (29.3k points)
Thanks! this worked for me.
+1 vote
by (106k points)

To convert int directly into float Python has a nice property where you can use // instead of single /.

0 votes
by (37.3k points)

Since i=0.0 in this case, i is a float. 

Thus, we are unable to use a float number to index a numpy array. 

Edit and redo the previous sentence.

     predictions[predictions > .5] = 1

    predictions[predictions <=.5] = 0

    # Change to an integer

    i = 0

    count = 0

    for hpred in heart["heartpred"]:

        if hpred == predictions[i]:

            count += 1

        i+=1

    accuracy=count/i

    print("Linear Regression Result:-")

    print("Accuracy = ")

    print(accuracy*100)

0 votes
by (37.3k points)

The correct answer is B. All of the options.

Understanding each of the following ideas is necessary to comprehend cloud computing:

Abstraction: Abstraction refers to hiding complex details from access.

Productivity: It helps users to focus, work faster, and collaborate easily.

Dependability: It refers to the fact that services are available online even if the issue occurs.

0 votes
by (1.3k points)

The “IndexError” that you are facing especially “only integer, slices (:), ellipsis (...), numpy.newaxis (None) and integer or boolean arrays are valid indices” indicates that there is a problem with how indices are being applied in your program. More often than not, this error occurs when one tries to index a NumPy Array with a floating value or an object which is not compatible for indexing. Let’s discuss the main ways to resolve those issues.

Main Challenges

  1. Repositional Indexing: In your code, there is a statement that uses a float index e.g. i = 0.0 and numericals index integer for indexing purposes.

  2. Updating KFold Usage: The way you are doing KFold is a bit old. Sklearn nowadays insists on the number of splits where the former was n_folds and random state issues are more straightforward.

Suggested Fixes

Thus, in order to rectify these problems and have your code working, do the following:

  1. Use Integer Indexing: Rather than starting i off with the value 0.0, initialize i as an integer. Also, use enumerate() in your loop to avoid using ugly indexing.

  2. Update KFold Setup: It is advised that the latest version of the syntax for KFold is used.

Here’s a new edition of your code which should work:

from sklearn.model_selection import KFold  # Updated import for KFold

# Updated KFold initialization

kf = KFold(n_splits=3, random_state=1, shuffle=True)

# Replace accuracy calculation loop with:

correct_predictions = np.sum(predictions == heart["heartpred"].values)  # Corrected comparison

accuracy = correct_predictions / len(heart)

# Remove the old accuracy calculation loop

Summary of Key Changes

Integer Indexing: Changed i to an integer, and added enumeration for cleaner loop structure.

Updated KFold Syntax: Used n_splits instead of the older n_folds.

Shuffed Data: Also enabled shuffle=True to allow splits in randomized order which can assist in model training.

Accuracy Calculation: Implemented np.sum for taking into account the predictions made and the target column for better accuracy.

This should correct the mistake and enhance the performance of your code.

3) Python void return type annotation

The wording is odd, particularly when it comes to the functions that do not have a return parameter. While one could argue that None is the most appropriate option due to the general portrayal of both its essence and functionality, there are also other ways to show that a function doesn’t return anything.

Annotated Versions of Functions That Do Not Return a Value

def foo() -> None: I think this is the simplest and the most common way of annotating the function which returns nothing. As for defines with no return, in Python – None means absence of value hence -> None means very clearly that function has nothing to return.

Code

def foo() -> None:

   print("This function does not return a value.")

def foo() -> type(None): While this works in practice, few will find it comfortable with the use of type(None). Most people would understand where using -> None is coming from rather than -> type(None) because None is the default already.

Code

def foo() -> type(None):

   print("This function does not return a value.")

def foo(): (no annotation) Similarly, if there is no need to specify types in all places, there is no issue in going without the return type. However, if return type annotations are already used, it is typically clearer and more consistent to specify a return type of -> None for functions which return no value.

Code

def foo():

   print("This function does not return a value.")

Conclusion

The recommended, most readable option is:

Code

def foo() -> None:

It is easy to employ the use of -> None, it is in line with the rules of python and it indicates to the user that the function does not return any value worth nothing. In addition, it helps the reader of the code to understand the code better, especially when tyaxe hints are being used within the whole codebase.

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