Recursion and closures in python3

Question

I am using env python 3.8.2 I can't get the value var in return

def a(x):

    def b():

        nonlocal x

        if x>2:

            print(x)

            return x

        x = x + 1

        b()

    return b

print(a(1)())

The result I am getting is:

4

None

I want to return value of x, but actually, it is None, even though the value printed is 4

Answer 1

Return b(). for the first time you will call b, it reaches b() but returns nothing, so your final return value is None.

def a(x):

    def b():

        nonlocal x

        if x>2:

            print(x)

            return x

        x = x + 1

        return b()

    return b

print(a(1)())

> 3

> 3

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