Special Characters in string literals

Question

I'm making a set in Python to house entire symbols on my keyboard, yet clearly, a couple of representing a few issues. Is there an approach to get them all in there without experiencing issues? 

Look at my set:

symbols = {`,~,!,@,#,$,%,^,&,*,(,),_,-,+,=,{,[,},},|,\,:,;,",',<,,,>,.,?,/}

To get around remarking out its vast majority, since in Python # is to comment, I encased everything like so: 

symbols = {'`','~','!','@','#','$','%','^','&','*','(',')','_','-','+','=','{','[','}','}','|','\',':',';','"',''','<',',','>','.','?','/'}

This works for that character, however now I would already be able to see an issue when I run over the ' and \. Is there a superior method to make this set?

Answer 1

You can actually fix the backslash punctuation line by getting away from it and ' can be fixed by placing it in double-quotes: 

symbols = {..., '\\', ... "'", ...}

However, composing this out is really dreary. Why not simply use string.punctuation all things being equal:

>>> from string import punctuation

>>> set(punctuation)

{'~', ':', "'", '+', '[', '\\', '@', '^', '{', '%', '(', '-', '"', '*', '|', ',', '&', '<', '`', '}', '.', '_', '=', ']', '!', '>', ';', '?', '#', '$', ')', '/'}

>>>

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