Check if a number is odd or even in python

Question

I to generate a program that will verify if a word is a palindrome or not. I can able to generate that code and it is working with words that have an even quantity of numbers. I want guidance on how to find out if a number is odd. Is there any simple way to find if a number is odd or even?

My code:

a = 0

while a == 0:

    print("\n \n" * 100)

    print("Please enter a word to check if it is a palindrome: ")

    word = input("?: ")

    wordLength = int(len(word))

    finalWordLength = int(wordLength / 2)

    firstHalf = word[:finalWordLength]

    secondHalf = word[finalWordLength + 1:]

    secondHalf = secondHalf[::-1]

    print(firstHalf)

    print(secondHalf)

    if firstHalf == secondHalf:

        print("This is a palindrom")

    else:

        print("This is not a palindrom")

    print("Press enter to restart")

    input()

Answer 1

A simple solution is to check if the number is even or not. For that, you can use the % sign, which is just like division and it will calculate the remainder, so if the number divided by 2 has a remainder of 0. 

if num % 2 == 0:

    pass # Even 

else:

    pass # Odd

Or you can also use this:

if num % 2:

    pass # Odd

else:

    pass # Even 

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