Combine two strings in python

Question

Consider the below list 1,

list1 = [('my', '1.2.3', 2),('name', '9.8.7', 3)]

I also need to get a new list2 like below,

list2 = [('my2', 2),('name8', 3)]

In the first step, I'm attempting to combine the first two elements inside a tuple,

for i,j,k in list1:

    #print(i,j,k)

    x = j.split('.')[1]

    y = str(i).join(x)

    print(y)

But I get this,

2

8

But, What I expect

my2

name8

I don't know, where I went wrong?

Answer 1

To resolve the issue in your code, you need to make a small modification. The problem lies in the line y = str(i).join(x). Instead, you should use the join() method on an empty string and pass i and x as arguments to concatenate them correctly.

Here's the updated code:

list1 = [('my', '1.2.3', 2), ('name', '9.8.7', 3)]

list2 = []

for i, j, k in list1:

    x = j.split('.')[1]

    y = ''.join([str(i), x])  # Concatenate i and x using ''.join()

    list2.append((y, k))

print(list2)

This will give you the expected output:

[('my2', 2), ('name8', 3)]

In the revised code, y = ''.join([str(i), x]) creates a new string by concatenating i and x without any separator. The resulting string is then added to list2 along with the corresponding value of k.

Answer 2

You can try,

y=str(i)+str(x)

It will work

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Answer 3

The issue in your code lies in the line y = str(i).join(x). The join() method is being called on the string representation of i, which is causing unexpected behavior. Instead, you should use the join() method on an empty string and pass i and x as arguments to concatenate them together.

Here's the corrected code:

list1 = [('my', '1.2.3', 2), ('name', '9.8.7', 3)]

list2 = []

for i, j, k in list1:

    x = j.split('.')[1]

    y = ''.join([str(i), x])  # Concatenate i and x using ''.join()

    list2.append((y, k))

print(list2)

This will produce the expected output:

[('my2', 2), ('name8', 3)]

In the corrected code, y = ''.join([str(i), x]) creates a new string by concatenating i and x without any separator in between. The resulting string is then appended to list2 along with the corresponding value of k.

Answer 4

To fix the issue in your code, you need to modify the line y = str(i).join(x). The problem arises because you're calling the join() method on the string representation of i instead of using an empty string as the separator.

Here's a corrected code:

list1 = [('my', '1.2.3', 2), ('name', '9.8.7', 3)]

list2 = []

for i, j, k in list1:

    x = j.split('.')[1]

    y = ''.join([str(i), x])  # Concatenate i and x using an empty string as the separator

    list2.append((y, k))

print(list2)

This will give you the expected output:

[('my2', 2), ('name8', 3)]

In the updated code, y = ''.join([str(i), x]) creates a new string by concatenating i and x without any separator. The resulting string is then appended to list2 along with the corresponding value of k.