Pythonic way to check if a list is sorted or not

Question

Is there a pythonic approach to check if a rundown is as of now arranged in ASC or DESC 

listtimestamps = [1, 2, 3, 5, 6, 7]

something like isttimestamps.isSorted() which returns True or False. 

I need to include a rundown of timestamps for certain messages and check if the exchanges showed up in the right request.

Answer 1

In Python, you can utilize the sorted() function and the all() function to determine if a given list is already sorted either in ascending or descending order. Here's an alternative formulation:

listtimestamps = [1, 2, 3, 5, 6, 7]

def is_sorted(lst):

    return all(lst[i] <= lst[i+1] for i in range(len(lst)-1)) or all(lst[i] >= lst[i+1] for i in range(len(lst)-1))

print(is_sorted(listtimestamps))  # Output: True

By employing a list comprehension along with the all() function, the function is_sorted() checks if each element in the list meets the specified condition: either each element is less than or equal to the next element (ascending order) or each element is greater than or equal to the next element (descending order). If the condition holds for all elements, the function returns True, indicating that the list is sorted; otherwise, it returns False.

In the given example, is_sorted(listtimestamps) returns True since the listtimestamps list is sorted in ascending order.

Answer 2

Check the below code:

all(l[i] <= l[i+1] for i in xrange(len(l)-1))

For python 3:

all(l[i] <= l[i+1] for i in range(len(l)-1))

Are you pretty much interested to learn python in detail? Come and join the python training course to gain more knowledge.

For more details, do check out the below video tutorial...

Answer 3

In Python, you can use the sorted() function and the all() function to check if a list is already sorted in ascending or descending order. Here's an example:

listtimestamps = [1, 2, 3, 5, 6, 7]

def is_sorted(lst):

    return lst == sorted(lst) or lst == sorted(lst, reverse=True)

print(is_sorted(listtimestamps))  # Output: True

The sorted(lst) function returns a sorted version of the list in ascending order, while sorted(lst, reverse=True) returns a sorted version in descending order. By comparing the original list with both sorted versions using lst == sorted(lst) and lst == sorted(lst, reverse=True), you can determine if the list is sorted in either ascending or descending order. The is_sorted() function returns True if the list is sorted and False otherwise.

In the example above, is_sorted(listtimestamps) returns True since the listtimestamps list is sorted in ascending order.

Answer 4

To check if a list is sorted in ascending or descending order in Python, you can use a concise approach:

listtimestamps = [1, 2, 3, 5, 6, 7] is_sorted = listtimestamps == sorted(listtimestamps) or listtimestamps == sorted(listtimestamps, reverse=True)

In this code, the sorted() function is applied to the list to obtain a sorted version in either ascending or descending order. By comparing the original list with both sorted versions, you can determine if it is sorted. The result is stored in the is_sorted variable, which will be True if the list is sorted and False otherwise.