AWS Java SDK - Unable to find a region via the region provider chain

Question

I have gone through the question titled "Setting the AWS region programmatically 1" but it doesn't provide all the answers I need.

Q1: I'm getting an SDKClientException-Unable to find a region via the region provider chain. What am I doing wrong? or is there a typo that I missed.

public class CreateS3Bucket {

public static void main(String[] args) throws IOException {

    BasicAWSCredentials creds = new BasicAWSCredentials("aws-access-key", "aws-secret-key");

    AmazonS3 s3Client = AmazonS3ClientBuilder.standard().withCredentials(new AWSStaticCredentialsProvider(creds)).build();

    Region region = Region.getRegion(Regions.US_EAST_1);

    s3Client.setRegion(region);

    try {

        String bucketName = "testBucket" + UUID.randomUUID();

        s3Client.createBucket(bucketName);

        System.out.println("Bucket Created Successfully.");

    } catch(AmazonServiceException awse) {

        System.out.println("This means that your request made it AWS S3 but got rejected");

        System.out.println("Error Message:" +awse.getMessage());

        System.out.println("Error Message:" +awse.getErrorCode());

        System.out.println("Error Message:" +awse.getErrorType());

        System.out.println("Error Message:" +awse.getRequestId());

    } catch (AmazonClientException ace) {

        System.out.println("The Amazon Client encountered an Error with network Connectivity");

        System.out.println("Error Message:" + ace.getMessage());

    }

 

}

}

Q2: What code changes needs to be done if I want to build a Lambda Function out of it? I'm aware of how to create a lambda function and roles that it needs. Just need to know if the code that I have written needs to change. How should I implement the LambdaFuctionHandler class as below:

import com.amazonaws.services.lambda.runtime.Context;

import com.amazonaws.services.lambda.runtime.RequestHandler;

 public class LambdaFunctionHandler implements RequestHandler<String, String> {

@Override

public String handleRequest(String input, Context context) {

    context.getLogger().log("Input: " + input);

 

    return null;

}

}

Answer 1

Build your client using the following syntax:

AmazonS3 amazonS3 = AmazonS3Client.builder()

    .withRegion("us-east-1")

    .withCredentials(new AWSStaticCredentialsProvider(creds))

    .build();