Check if a number is a perfect square

Question

I want to check if a number is a perfect square or not. How we can do that?

Answer 1

You can create your own function that will evaluate weather the number is a perfect number or not:

def is_square(apositiveint):

  x = apositiveint // 2

  seen = set([x])

  while x * x != apositiveint:

    x = (x + (apositiveint // x)) // 2

    if x in seen: return False

    seen.add(x)

  return True

for i in range(110, 130):

   print i, is_square(i)

 If you are newbie and want to explore more about Python, then learn python from the below video tutorial: