The issue in your code lies with the line reals = s[0:n+1]. It should be reals = inters[0:n] instead.
The reason for the correction is that inters is the concatenated string obtained by repeating string s n times. So, to count the number of 'a's correctly, you should consider reals as a slice of inters from index 0 to index n-1. By using s[0:n+1], you are not considering the concatenated string inters but rather the original string s.
Here's the corrected code:
def repeatedString(s, n):
count = 0
inters = s * n
reals = inters[0:n]
for i in reals:
if i == 'a':
count += 1
return count
s = "aba"
n = 10
result = repeatedString(s, n)
print("The number of 'a's in the repeated string is:", result)
With this correction, the code should correctly count the number of 'a's in the repeated string. In the provided example, it will output 7, which is the expected result.