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In Python, hHow to create a zip archive of a directory structure?

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To create a zip archive of a directory you can use the shutil.make_archive() the function which supports the zip format. Below is the code for the same. 

import shutil

shutil.make_archive(output_filename, 'zip', dir_name)

Another way is by using the zipfile. Below I have given the code that shows you how it can be used:

#!/usr/bin/env python

import os

import zipfile

def zipdir(path, ziph):

    for root, dirs, files in os.walk(path):

          for file in files:

                ziph.write(os.path.join(root, file)) 

if __name__ == '__main__':  #This is driver code

       zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)

       zipdir('tmp/', zipf)

       zipf.close()

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by (108k points)
edited by

I would suggest you use the zipfile module from python. Kindly check the below code for reference:

#!/usr/bin/env python

import os

import zipfile

def zipdir(path, ziph):

    # ziph is zipfile handle

    for root, dirs, files in os.walk(path):

        for file in files:

            ziph.write(os.path.join(root, file))

if __name__ == '__main__':

    zipf = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)

    zipdir('tmp/', zipf)

    zipf.close()

Are you interested to learn Python in detail? Do check out the below video for more insights:

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