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I'm trying to use the sort feature when querying my MongoDB, but it is failing. The same query works in the MongoDB console but not here. Code is as follows:

import pymongo 

from pymongo import Connection 

connection = Connection() 

db = connection.myDB 

print db.posts.count() 

for post in db.posts.find({}, {'entities.user_mentions.screen_name':1}).sort({u'entities.user_mentions.screen_name':1}): 

print post

The error I get is as follows:

Traceback (most recent call last): 

File "find_ow.py", line 7, in <module> 

for post in db.posts.find({}, {'entities.user_mentions.screen_name':1}).sort({'entities.user_mentions.screen_name':1},1): 

File "/Library/Python/2.6/site-packages/pymongo-2.0.1-py2.6-macosx-10.6-universal.egg/pymongo/cursor.py", line 430, in sort File "/Library/Python/2.6/site-packages/pymongo-2.0.1-py2.6-macosx-10.6-universal.egg/pymongo/helpers.py", line 67, in _index_document 

TypeError: first item in each key pair must be a string

I found a link elsewhere that says I need to place a 'u' in front of the key if using pymongo, but that didn't work either. Anyone else gets this to work or is this a bug.

2 Answers

0 votes
by (107k points)

If you want to sort MongoDB with pymongo you can use the below-mentioned way:-

The .sort(), in pymongo, takes key and direction as parameters.

So if you want to sort by, let's say, id then you should .sort("_id", 1)

For multiple fields:

.sort([("field1", pymongo.ASCENDING), ("field2", pymongo.DESCENDING)])

0 votes
by (92.8k points)

You can also try the following code:




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