Log to the base 2 in python

Question

How should I compute log to the base two in python. Eg. I have this equation where I am using log base 2

import math

e = -(t/T)* math.log((t/T)[, 2])

Answer 1

Package math.log takes an optional second argument which allows you to specify the base:

In [22]: import math

In [23]: math.log?

Type:       builtin_function_or_method

Base Class: <type 'builtin_function_or_method'>

String Form:    <built-in function log>

Namespace:  Interactive

Docstring:

    log(x[, base]) -> the logarithm of x to the given base.

    If the base not specified, returns the natural logarithm (base e) of x.

In [25]: math.log(8,2)

Out[25]: 3.0

Answer 2

You can use the below-mentioned code:-

import math 

log2 = math.log(x, 2.0) 

log2 = math.log2(x)