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I have a list where I want to replace values with None where condition() returns True.

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

For example, if condition checks bool(item%2) should return:

[None, 1, None, 3, None, 5, None, 7, None, 9, None]

What is the most efficient way to do this?

1 Answer

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by (20.3k points)

Try using the code given below:

ls = [x if (condition) else None for x in ls]

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