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in Java by (10.2k points)

The question is best explained by an example:

In Java for a JPA EntityManager, I can do the following(Account is my Entity class):

Account result = manager.find(Account.class, primaryKey);

In Scala, my naive attempt is:

val result = manager.find(Account.class, primaryKey)

But when I try to use Account.class in Scala, it seems to not like this. How can I specify the java.lang.Class object for the Account class in Scala?

1 Answer

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classOf[Account] in Scala is equivalent to Account.class in Java.

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