How to pass keyword arguments with illegal names to a function accepting **kwargs

Question

The context is complex to explain, but tl;dr I have to deal with the production system where I cannot install libraries and one of my libraries expects illegal keyword arguments as the input.

def hack_me(**kwargs):

   if kwargs.get("hack:/me") is not None:

      print("Hacked!")

The objective is that my function above, without modifying it, prints Hacked!.

Answer 1

While your regular arguments can't have any form for their name, expanded arguments using a same syntax as in the function signature (i.e. **args) can.

>>> args = {'hack:/me': True}

>>> hack_me(**args)

Hacked!

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