Intellipaat Back

Explore Courses Blog Tutorials Interview Questions
0 votes
2 views
in SQL by (6.1k points)

I have these following three tables named

**Student Table**
-------------
id    name
-------------
1     ali
2     ahmed
3     john
4     king

**Course Table**
-------------
id    name
-------------
1     physic
2     maths
3     computer
4     chemistry

**Bridge**
-------------
sid    cid
-------------
1     1
1     2
1     3
1     4
2     1
2     2
3     3
3     4
4     1
4     2

Now to display the student name with the course name which he had studied like,

**Result**
---------------------------
Student        Course
---------------------------
ahmed         physic
ahmed         maths
ahmed         computer
ahmed         chemistry
ali           physic
ali           maths
john          computer
john          chemistry
king          physic
king          maths

I make the following query

select s.name as Student, c.name as Course from student s, course c join bridge b on c.id = b.cid order by s.name

Though it does not return the expected result...

And what would be for the normalized form, if I need to determine who is the manager over other:

**employee**
-------------------
id        name
-------------------
1         ali
2         king
3         mak
4         sam
5         jon

**manage**
--------------
mid      eid
--------------
1         2
1         3
3         4
4         5

And I need to get this following result:

**result**
--------------------
Manager      Staff
--------------------
ali          king
ali          mak
mak          sam
sam          jon

1 Answer

0 votes
by (12.7k points)

You can use the following code:

select s.name "Student", c.name "Course"
from student s, bridge b, course c
where b.sid = s.sid and b.cid = c.cid 

Want to know more about SQL? Join this SQL Course by Intellipaat.

You can also go through the below MySQL tutorial video that will help you out in a better way:

Related questions

0 votes
1 answer
0 votes
1 answer
0 votes
1 answer
0 votes
1 answer
0 votes
1 answer
asked Jul 6, 2019 in SQL by Tech4ever (20.3k points)

31k questions

32.8k answers

501 comments

693 users

Browse Categories

...