How to pass command line arguments in Python 3.x?

Question

I don't know, why I'm not getting the output for this below program?

from sys import argv

script, first, second, third = argv

print ("The script is called:", script)

print ("Your first variable is:", first)

print ("Your second variable is:", second)

print ("Your third variable is:", third)

Can anyone tell me, How to utilize cmd to pass the arguments?

Answer 1

You were calling it like,

python program.py a1 b2 c3

where it outputs

The script is called: /home/sophia/program.py

Your first variable is: a1

Your second variable is: b2

Your third variable is: c3

sys.argv contains a rundown of strings, each comparing to a command line boundary. The first is consistently the filename of the content; others are the discretionary parameters, requested precisely as they were composed in a shell.

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