Back

Explore Courses Blog Tutorials Interview Questions
0 votes
2 views
in Python by (12.7k points)

How the measurement/dimension is 1. I have given a condition of 3 factors/variables it implies it is a 3 dimension however it is showing the measurement/dimension as 1. Would anyone be able to reveal to me the rationale of ndim?

import numpy as np

>>> a=np.array([1,2,3,4])

>>> a

array([1, 2, 3, 4])

>>> a.ndim

1

1 Answer

0 votes
by (26.4k points)

According to the numpy docs, numpy.ndim(a) will returns:

The number of dimensions in a. Scalars are zero-dimensional

e.g.:

a = np.array(111)

b = np.array([1,2])

c = np.array([[1,2], [4,5]])

d = np.array([[1,2,3,], [4,5]])

print a.ndim, b.ndim, c.ndim, d.ndim

#outputs: 0 1 2 1

Here, the last array d is a variety of object dtype, so its dimension is as yet 1

What you wanna use could be a.shape (or a.size for a one-dimensional exhibit/array):

print a.size, b.size

print c.size # == 4, which is the total number of elements in the array

#outputs:

1 2

4

Here, the method .shape will returns you a tuple, you ought to get your measurement utilizing [0]:

print a.shape, b.shape, b.shape[0]

() (2L,) 2

Wanna become a Python expert? Come and join the python certification course and get certified.

For more details, do check out the below video tutorial...

Related questions

0 votes
2 answers
0 votes
1 answer
0 votes
1 answer
0 votes
1 answer
asked Mar 21, 2021 in Python by laddulakshana (12.7k points)
Welcome to Intellipaat Community. Get your technical queries answered by top developers!

29.3k questions

30.6k answers

501 comments

104k users

Browse Categories

...