Order Crossover (OX) - genetic algorithm

Question

Can someone explain to me how Order Crossover works? I will give this example and I want to understand it in a generic way to implement after.

Parent 1 = 1 2 3 | 4 5 6 7 | 8 9

Parent 2 = 4 5 2 | 1 8 7 6 | 9 3

and the solution are two childreen:

Children 1 = 2 1 8 | 4 5 6 7 | 9 3

Children 2 = 3 4 5 | 1 8 7 6 | 9 2

I understand some parts but others not.

Thanks

Answer 1

Order 1 Crossover is a fairly simple permutation crossover. A swath of consecutive alleles from parent 1 falls, and remaining values are stored in the child in the order which they appear in parent 2.

1. Select a random swath of consecutive alleles from parent 1. (underlined)

2. Drop the swath down to Child 1 and mark out these alleles in Parent 2.

3. Starting on the right side of the swath, grab alleles from parent 2 and insert them in Child 1 at the right edge of the swath. Since 8 is in that position in Parent 2, it is inserted into Child 1 first at the right edge of the swath. Notice that alleles 1, 2 and 3 are skipped because they are marked out and 4 is inserted into the 2nd spot in Child 1.

4.  If you desire a second child from the two parents, flip Parent 1 and Parent 2 and go back to Step 1.

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