sys.argv[1] meaning in script

Question

I'm currently teaching myself Python and was just wondering (In reference to my example below) in simplified terms what the sys.argv[1] represents. Is it simply asking for input?

#!/usr/bin/python3.1 

# import modules used here -- sys is a very standard one 

import sys 

# Gather our code in a main() function 

def main(): 

print ('Hello there', sys.argv[1]) 

# Command line args are in sys.argv[1], sys.argv[2] .. 

# sys.argv[0] is the script name itself and can be ignored 

# Standard boilerplate to call the main() function to begin 

# the program. 

if __name__ == '__main__': 

main()

Answer 1

The meaning of sys.argv[1] contains the first command-line argument passed to your script.

For example, if your script is named hello.py and your issue:

$ python3.1 hello.py foo

or:

$ chmod +x hello.py

$ ./hello.py foo

Your script will print:

Hello there foo

To know more about this you can have a look at the following video tutorial:-