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0 votes
in Python by (580 points)

I've got a list of Python objects which I would like to sort by an attribute of the objects themselves. The list is as follows:

>>> nt

[<Tag: 128>, <Tag: 2008>, <Tag: <>, <Tag: actionscript>, <Tag: addresses>,

 <Tag: aes>, <Tag: ajax> ...]


Each object has a count:


>>> nt[1].count



I want the list be sorted by number of counts descending.Can anyone help?

1 Answer

0 votes
by (10.9k points)

You can use the sort() method to sort a list in place.

nt.sort(key=lambda x: x.count, reverse=True)


Alternatively, you can use the sorted() built-in function to return a new sorted list.

sorted_list = sorted(nt, key=lambda x: x.count, reverse=True) 

To know more about sorting in python take a look here:

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