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In python,Can anyone tell me how to merge two sorted linked list into one Linked list?

Look at the below code:

return None

else:

else:

else:

return temp

pass

the issue here is stucked in the endless loop.can anyone mention to me what the issue is

Examples are:

assert [] == merge_lists([],[])

assert [1,2,3] == merge_lists([1,2,3], [])

assert [1,2,3] == merge_lists([], [1,2,3])

assert [1,1,2,2,3,3,4,5] == merge_lists([1,2,3], [1,2,3,4,5])

closed

by (19k points)

Given below is the code for Merging two sorted linked lists into one linked list in python:

return None

else:

temp = temp.next

by (26.4k points)

The issue with the current code is that it causes a result of the temp node's next before it explores the following node from the current hub. This is dangerous when the current temp node is the current node.

Imagine this case,

temp = N

temp.next = N  # which means N.next = N

N = N.next     # but from above N = (N.next = N) -> N = N

Check the below code for corrected version.

# create dummy node to avoid additional checks in loop

s = t = node()

# remember current low-node

else:

# remember current low-node

# only mutate the node AFTER we have followed ->next

t.next = c

# and make sure we also advance the temp

t = t.next

# return tail of dummy node

return s.next

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by (25.7k points)
The issue causing the endless loop in the provided code is that the temp variable is not being updated correctly within the while loop. This prevents the merged linked list from being constructed properly.

To fix the issue, you need to update the temp variable within each iteration of the loop to keep track of the current tail node of the merged list. Here's the corrected code:

return None

else:

else:

temp = temp.next  # Update temp to the current tail node

else:

Now the code correctly updates the temp variable within the loop, ensuring that the merged linked list is constructed properly.

The provided test cases should now work correctly with the corrected code.
by (15.4k points)
Here's a  code along with an explanation of the issue and the fix:

return None

else:

temp = merged_head  # Keep track of the current tail node of the merged list

else:

temp = temp.next  # Update temp to the current tail node

else:

Explanation:

The provided code attempted to merge two sorted linked lists into a single linked list. However, it had an issue with an endless loop due to not correctly updating the temp variable within the while loop. This caused the merged linked list to be constructed incorrectly.

To fix the issue, the code has been modified to update the temp variable correctly within each iteration of the loop. This ensures that the current tail node of the merged list is maintained and that the merged linked list is constructed accurately.