Armstrong Number python

Question

The main question is that we need to print the first Armstrong number in the range of 1042000 to 702648265 and terminate the loop as soon as we meet the first Armstrong number. Use while loop

This is my code :

upper = 702648265

lowers=1042000

for num in range (lower, upper + 1):

    o= len (str(num))

    sum = 0

    temp = num

    while temp > 0:

        x = temp % 10

        sum += x ** o

        temp //= 10

    if num == sum:

        print(num)

        break

Output:

1741725

I got 1741725 answers in my output. but when I check Armstrong's number mathematically it's the wrong answer. 

Answer 1

Your answer is right. Your code still needs to be improved a bit.

Your code:

upper = 702648265

lowers=1042000

for num in range (lower, upper + 1):

Corrected code:

upper = 702648265

lowers=1042000

for num in range (lowers, upper + 1): #it should be lowered instead of lower

Here o is 7. So you have to calculate to the power of 7 on each number

1 ^ 7 + 7 ^ 7 + 4 ^ 7 + 1 ^ 7 + 7 ^ 7 + 2 ^ 7 + 5 ^ 7

= 1 + 823543 + 16384 + 1 + 823543 + 128 + 78125

= 1741725

So the answer is correct. 

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